NCERT Solutions For Class 10 Maths Chapter 6 Triangles Ex 6.3

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NCERT Solutions For Class 10 Maths Chapter 6 Triangles Ex 6.3

Get Free NCERT Solutions for Class 10 Maths Chapter 6 Ex 6.3 PDF. Triangles Class 10 Maths NCERT Solutions are extremely helpful while doing your homework. Exercise 6.3 Class 10 Maths NCERT Solutions were prepared by Experienced ncert-books.inTeachers. Detailed answers of all the questions in Chapter 6 Maths Class 10 Triangles Exercise 6.3 provided in NCERT TextBook.

NCERT Solutions For Class 10 Maths Chapter 6 Triangles Ex 6.3

NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex Ex 6.3 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.3

Question 1.
State which pairs of triangles in the given figures are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form :
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 20
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 21
Solution:
NCERT Solutions for Class 10 Maths Chapter 6 pdf Triangles Ex 6.3 Q1
NCERT Solutions for Class 10 Maths Chapter 6 pdf Triangles Ex 6.3 Q1.1

 

Question 2.
In the given figure, ∆ODC ~ ∆OBA, ∠BOC = 125° and ∠CDO = 70°. Find ∠DOC, ∠DCO and ∠OAB.
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 25Solution:
Ex 6.3 Class 10 Maths NCERT Solutions PDF Q2

 

Question 3.
Diagonals AC and BD of a trape∠ium ABCD with AB || DC intersect each other at the point O. Using a similarity criterion for two triangles, show that \frac { OA }{ OC } =\frac { OB }{ OD^{ \bullet } }
Solution:
Ex 6.3 Class 10 Maths NCERT Solutions PDF Q3

Question 4.
In the given figure, \frac { QR }{ QS } =\frac { QT }{ PR } and ∠1 = ∠2. show that ∆PQR ~ ∆TQR.
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 29Solution:
Ex 6.3 Class 10 Maths NCERT Solutions PDF Q4

Question 5.
S and T are points on sides PR and QR of ∆PQR such that ∠P = ∠RTS. Show that ∆RPQ ~ ∆RTS.
Solution:
Exercise 6.3 Class 10 Maths NCERT Solutions PDF Q5

Question 6.
In the given figure, if ∆ABE ≅ ∆ACD, show that ∆ADE ~ ∆ABC.
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 33Solution:
Exercise 6.3 Class 10 Maths NCERT Solutions PDF Q6

Question 7.
In the given figure, altitudes AD and CE of ∆ABC intersect each other at the point P. Show that:
(i) ∆AEP ~ ∆CDP
(ii) ∆ABD ~ ∆CBE
(iii) ∆AEP ~ ∆ADB
(iv) ∆PDC ~ ∆BEC
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 35Solution:
Exercise 6.3 Class 10 Maths NCERT Solutions PDF Q7

Question 8.
E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ∆ABE ~ ∆CFB.
Solution:
Triangles Class 10 Ex 6.3 NCERT Solutions PDF Q8

Question 9.
In the given figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that:
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 38
Solution:
Triangles Class 10 Ex 6.3 NCERT Solutions PDF Q9

Question 10.
CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ∆ABC and ∆EFG respectively. If ∆ABC ~ ∆FEG, show that
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 40
Solution:
Triangles Class 10 Ex 6.3 NCERT Solutions PDF Q10
Triangles Class 10 Ex 6.3 NCERT Solutions PDF Q10.1

Question 11.
In the given figure, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD ⊥ BC and EF ⊥ AC, prove that ∆ABD ~ ∆ECF.
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 43Solution:
Chapter 6 Maths Class 10 Ex 6.3 NCERT Solutions PDF Q11

Question 12.
Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of ∆PQR (see in given figure). Show that ∆ABC ~ ∆bPQR.
NCERT Solutions for Class 10 Maths Chapter 6 Triangles 45Solution:
Chapter 6 Maths Class 10 Ex 6.3 NCERT Solutions PDF Q12

Question 13.
D is a point on the side BC of a triangle ABC, such that ∠ADC = ∠BAC. Show that CA² = CB.CD.
Solution:
Chapter 6 Maths Class 10 Ex 6.3 NCERT Solutions PDF Q13

Question 14.
Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR. Show that ∆ABC ~ ∆PQR.
Solution:
Ch 6 Maths Class 10 Ex 6.3 NCERT Solutions PDF Q14

Question 15.
A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.
Solution:
Ch 6 Maths Class 10 Ex 6.3 NCERT Solutions PDF Q15

Question 16.
If AD and PM are medians of triangles ABC and PQR respectively, where
∆ABC ~ ∆PQR. Prove that \frac { AB }{ PQ } =\frac { AD }{ P{ M }^{ \bullet } }
Solution:
Class 10 Maths Chapter 6 Ex 6.3 NCERT Solutions PDF Q16

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