NCERT Solutions for Class 11 Maths Chapter 7 Permutation and Combinations
NCERT Solutions for Class 11 Maths Chapter 7 Exercise.7.1
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NCERT Solutions for Class 11 Maths Chapter 7 Exercise.7.2
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NCERT Solutions for Class 11 Maths Chapter 7 Exercise.7.3
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NCERT Solutions for Class 11 Maths Chapter 7 Exercise.7.4
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NCERT Solutions for Class 11 Maths Chapter 7 Miscellaneous Solutions
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Exercise- 7.1
Q-1: Form 3- digit numbers by using digits 4, 5, 6, 7 and 8 and assume that
(i) The digits can be repeated.
(ii) Digits can’t be repeated in the 3- digit number.
Q-2: Form a 3- digit number which should be even by using 1, 2, 3, 6, 8, and 9. Note that, repetition of digits is allowed.
Q-3: Find the total number of 4- letter code formed by using the 10 English alphabets, i.e., a, b, c, d, e, f, g, h, i and j. Assume that the repetition of the letters of English alphabet is not allowed.
Q-4: Find the total number of 5- digit telephone numbers formed by using the numbers from 0 to 9. Note that, each of the telephone number will start with 36 and the repetition of the numbers is not allowed.
Q-5: Consider a scenario when a person tosses a coin. He tosses the coin for two times and every time the outcome of the toss is recorded by one of his friend. Find the total number of possible outcomes of the coin his friend will record.
Q-6: Consider 5 flags which are of different colors. Find the total possibility of getting different signals. Note that, each of the signals requires the use of any two flags at the same time, one after the other.
EXERCISE- 7.2
Q-1: Evaluate:
(i). 8! (ii). 4! – 3!
Q-2: Is 3! + 4! = 7! ?
EXERCISE – 7.3
Q-1: If there is no repetition of numbers, then find the total of 3- digit numbers formed by using digits from 2 to 9.
Q-2: Find the total number of 4- digits numbers where there is no repetition of digits.
Q-3: Find the total number of 3- digit number which is even and is formed by using the digits 2, 3, 4, 5, 6, 7 and 8. Note that repetition of digit is restricted.
Q-4: How many 4- digit numbers will be formed by using the digits 2, 3, 4, 5 and 6. Note that, repetition of digits is not allowed. Find among those numbers, how many numbers will be even number?
Q-5: Consider a committee with 9 persons, in how many ways can we choose a chairman and a vice chairman? Note that, a person can hold only one position at a time.
Q-8: Get all the number of ways, with or without the meaning, which might be formed by using the letters from the word EQUATION. Note that, repetition of the word is restricted.
Q-9: Find the number of words, with or without the meaning, which might be formed by using the letters from the word MONDAY. Note that, repetition of the word is restricted, if
(i) At a time, 3 letters can be used.
(ii) All the letters can be used at a time.
(iii) First letter is a vowel and all the letters are being used.
Q-10: Find the number of distinct permutations such that 4 I’s does not come together in the word MISSISSIPPI.
Q-11: Arrange the letters of the word PERMUTATIONS and observe the number of ways of the permutation if,
(i). the new word starts with P and ends with S.
(ii). when the vowels are taken all together.
(iii). there will always be 4 letters between P and S.
EXERCISE – 7.4
Q-3: Find total number of chords which can be drawn through 21 points on the circle.
Q-4: Find the number of ways in which a team of 2 boys and 2 girls can be selected from the group of 5 boys and 4 girls.
Q-5: In how many ways will 9 balls be selected from 7 red balls, 6 blue balls and 5 white balls if every time 3 balls of different colors be selected?
Q-6: Find out the number of combinations of 5 cards from a deck of 52 cards. Assume that there is at least one ace in each of the combinations.
Q-7: Find the number of ways by which one can select a cricket team of 11 players from a bunch of 17 players among which only 5 players can bowl if every cricket team of 11 players must have exactly 4 bowlers.
Q-8: There are 6 black and 5 red balls. Find the number of ways through which 3 black and 3 red balls will be selected.
Q-9: Find the number of ways by which a student can choose a program of 5 courses, if there are options of 10 courses and for every student 2 courses are made compulsory.
MISCELLANEOUS EXERCISE
Q-1: Find the number of words, having meaning or meaningless, each of 2 vowels and 4 consonants will be formed by the letters of the word DAUGHTER?
Q-2: Find the number of words, which can be either meaningful or meaningless, which will be formed by using all of the letters of the word EQUATION at a time such that both the vowel and the consonant will occur together.
Q-3: There are 10 boys and 5 girls through which a committee with 7 members has to be formed. Now, find the number of ways in which this might be created when the committee formed consists of:
(i) Exactly 4 girls (ii) at least 4 girls (iii) almost 4 girls?
Q-4: In a dictionary, the permutation of the letters of the word EXAMINATION is listed, then find the total number of words in the list of dictionary before the first letter of the word start with E.
Q-5: Find the total number of 6- digit numbers formed by using the digits 0, 2, 3, 4, 5 and 6 which should be divisible by 10. Note that, the repetition of digit is not allowed.
Q-6: It is known that the English alphabet has 21 consonants and 5 vowels. Find the number of words formed with 4 different consonants and 3 different vowels from the English alphabet.
Q-7: There are 12 questions in the question paper of an examination which is mainly divided into two parts, say, part-I and part-II, each having 4 and 8 questions, respectively. There is a condition given in the question paper that the student has to attempt at least 8 questions for sure, selection 3 from each section. Now, find the number of ways in which a student can select the questions in the question paper.
Q-8: Find the number of ways of 5- card combinations from a deck of 52 cards. Note that, among those 5 cards, there must be exactly one king in the combination.
Q-9: Consider a situation in which 7 men and 6 women needs to be seated in a row in such a way that the women will occupy the even places.
Q-10: There are 20 students in a class from which 8 students will be chosen for an exclusion party. 3 students from the class decided that either they will join combinely or none of them will go for the exclusion party. Find the number of ways by which the exclusion party will be chosen.
Q-11: Arrange ASSASSINATION in such a way that all the S’s are filled together. Find the number ways for the arrangement of S’s together.