NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.2

NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

Exercise 14.2

Ex 14.2 Class 6 Maths Question 1.
Draw a line segment of length 7.3 cm using ruler.
Solution:
Step I: Mark at point P.
Step II : Place the O mark of the ruler against the point P.
Step III : Mark a point Q at a distance of 7.3 cm from P.
Step IV : Join P and Q.

Thus $\overline { PQ }$ is the line segment of length 7.3 cm.

Ex 14.2 Class 6 Maths Question 2.
Construct a line segment of length 5.6 cm using ruler and compass.
Solution:
Step I: Draw any line L of suitable lengths.
Step II : Place the needle of the compass on the zero mark of the ruler and open it upto 5.6 mark.
Step III : Place the needle at any point A at the line and draw an arc to cut l at B.

Thus, $\overline { AB }$ is the required line segment of length 5.6 cm.

Ex 14.2 Class 6 Maths Question 3.
Construct $\overline { AB }$ of length 7.8 cm. From this, cut off $\overline { AC }$ of length 4.7 cm. Measure $\overline { BC }$ .
Solution:
Given that $\overline { AB }$ = 7.8 cm and $\overline { AC }$ = 4.7 cm.
Step I : Place zero mark of the ruler at A.
Step II : Mark a point B at a distance of 7.8 cm from A.
Step III : Mark another point C at a distance of 4.7 cm from A such that AC = 4.7 cm.
Step IV : On measuring the length of BC, we find that $\overline { BC }$ = 3.1 cm.

Ex 14.2 Class 6 Maths Question 4.
Given $\overline { AB }$ of length 3.9 cm. Construct $\overline { PQ }$ such that the length of $\overline { PQ }$ is twice that of $\overline { AB }$ . Verify by measurement.

(Hint : Construct $\overline { PX }$ such that the length of $\overline { PX }$ = length of $\overline { AB }$ then cut off $\overline { XQ }$ such that $\overline { XQ }$ also has the length of $\overline { AB }$ .
Solution:
Step I: Draw a line l of suitable length.
Step II: Draw $\overline { AB }$ = 3.9 cm
Step III: From the line, construct $\overline { PX }$ = $\overline { AB }$ = 3.9 cm.
Step IV: Again construct $\overline { XQ }$ = $\overline { AB }$ =3.9 cm
Verification: $\overline { PX }$ + $\overline { XQ }$ = $\overline { AB }$ + $\overline { AB }$

Thus twice of $\overline { AB }$ is equal to $\overline { PQ }$

Ex 14.2 Class 6 Maths Question 5.
Given $\overline { AB }$ of length 7.3 cm and $\overline { CD }$ of length 3.4 cm, construct a line segment $\overline { XY }$ such that the length of XY is equal to the difference between the length of $\overline { AB }$ and $\overline { CD }$ . Verify the measurement.
Solution:
Step I : Construct $\overline { AB }$ = 7.3 cm and $\overline { CD }$ = 3.4 cm.

Step II: Take a point P on the given line l.
Step III: Construct $\overline { PR }$ such that $\overline { PR }$ = $\overline { AB }$ = $\overline { AB }$ = 7.3 cm.
Step IV:Construct $\overline { RQ }$ = $\overline { CD }$ = 3.4 cm such that PQ = $\overline { AB }$ – $\overline { CD }$ .
Verification : On measuring, we observe that $\overline { PQ }$ = 3.9 cm = 7.3 cm 3.4 cm.
= $\overline { AB }$ – $\overline { CD }$
Thus, $\overline { PQ }$ = $\overline { AB }$ – $\overline { CD }$ .